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Predict the products of the following reactions. (i) CH3−C=OH2N−NH2−−−−−−−→ CH3(ii)C6H5−CH3(a)KMnO4/KOH−−−−−−−−−−−→(b)H+(iii) Ph−COOHBr2/FeBr3−−−−−−−→

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13. 111111,-LH CUOH/NH,CH,COO- K of a salt Ni(OH), is 2 x10-15 then molar solubility of Ni(OH), in 0.01M NaOH is :- (1) 2 x 10-15 M (2) 21/3 x 10-5 M. (3)

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Spelling 'k' spelt 'ch' — Crack the Code (Years 3-4)

The reaction CH_4(g)+Cl_2(g) → CH_3Cl(g) + HCl(g) has △ H= 25 kcal and bond dissociation energy of C Cl, H Cl, C H and Cl Cl is given as 84 kcal/mol, 103

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The products obtained in the reaction, C_{6}H_{5}-CH_{2}-CH _{3}xrightarrow[273,K]{Cl_{2},hv} is/are

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